Question

A

b
B
0
PC
Solve the right triangle shown in the figure.
BC= 1.6in, ZA = 48.8°C = 90°
a. AC=0.3in, B = 41.20, AB = 1.6in
b. AC=2.5in, ZB= 41.20, AB = 3.0in
C.
AC 1.4in, ZB= 41.20, AB= 2.1in
d. AC=2.5in, B = 41.2°, AB= 2.1in
Please select the best answer from the choices provided
=

Answer 1

Check the picture below.

`\tan(48.8^o )=\cfrac{\stackrel{opposite}{1.6}}{\underset{adjacent}{b}} \implies b=\cfrac{1.6}{\tan(48.8^o)}\implies b\approx 1.4 \\\\[-0.35em] ~\dotfill\\\\ \sin(48.8^o )=\cfrac{\stackrel{opposite}{1.6}}{\underset{hypotenuse}{c}} \implies c=\cfrac{1.6}{\sin(48.8^o)}\implies c\approx 2.1`

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