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3 similar rings and 2 similar bags cost $600. 1 ring and 1 bag cost $225. Find the cost of 1 bag.​

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Answer:

3r + 2b = 600 ---(1)

r + b = 225 ---(2)

We can solve this system of equations using substitution or elimination method.

Using substitution method, we can solve equation (2) for "r" in terms of "b":

r = 225 - b

Substituting this expression for "r" into equation (1), we get:

3(225 - b) + 2b = 600

Simplifying and solving for "b", we get:

675 - 3b + 2b = 600

-b = -75

b = $75

Therefore, the cost of one bag is $75.

Explanation:

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