230k views
0 votes
If f(x)=x²-3x and g(x) = 2 - x³, evaluate the following.

a. (f+g)(-3)
b. (g-f) (1)
c. (f•g) (-2)
d. (g/f) (1)

User Albie
by
7.7k points

1 Answer

5 votes

Answer:

a. (f+g)(-3) means we need to add the two functions f and g, and then evaluate the sum at x=-3. So, we have:

(f+g)(-3) = f(-3) + g(-3) = [(-3)² - 3(-3)] + [2 - (-3)³]

= [9 + 9] + [2 + 27]

= 46

Therefore, (f+g)(-3) = 46.

b. (g-f)(1) means we need to subtract the function f from g, and then evaluate the difference at x=1. So, we have:

(g-f)(1) = g(1) - f(1) = [2 - 1³] - [(1)² - 3(1)]

= [2 - 1] - [1 - 3]

= 3

Therefore, (g-f)(1) = 3.

c. (f•g)(-2) means we need to multiply the two functions f and g, and then evaluate the product at x=-2. So, we have:

(f•g)(-2) = f(-2) • g(-2) = [(-2)² - 3(-2)] • [2 - (-2)³]

= [4 + 6] • [2 + 8]

= 100

Therefore, (f•g)(-2) = 100.

d. (g/f)(1) means we need to divide the function g by f, and then evaluate the quotient at x=1. So, we have:

(g/f)(1) = g(1) / f(1) = [2 - 1³] / [(1)² - 3(1)]

= [2 - 1] / [-2]

= -1/2

Therefore, (g/f)(1) = -1/2.

Explanation:

use brain

User Fabio Picheli
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories