Answer:
AgCl = 0.0133 mol
Step-by-step explanation:
The balanced chemical equation for the reaction between AgNO3 and CaCl2 is:
AgNO3 + CaCl2 → AgCl + Ca(NO3)2
From the equation, we can see that 1 mole of AgNO3 reacts with 1 mole of CaCl2 to produce 1 mole of AgCl. Therefore, we need to determine the number of moles of AgNO3 and CaCl2 in the given volumes of solutions and use the stoichiometric coefficients to calculate the number of moles of AgCl produced.
First, let's calculate the number of moles of AgNO3 in 63.57 mL of 1.327 M solution:
moles of AgNO3 = volume (in L) x concentration
moles of AgNO3 = 63.57 mL x 1 L/1000 mL x 1.327 mol/L
moles of AgNO3 = 0.0844 mol
Next, let's calculate the number of moles of CaCl2 in 41.87 mL of 0.317 M solution:
moles of CaCl2 = volume (in L) x concentration
moles of CaCl2 = 41.87 mL x 1 L/1000 mL x 0.317 mol/L
moles of CaCl2 = 0.0133 mol
Since we have more AgNO3 than CaCl2, CaCl2 is the limiting reagent. Therefore, the number of moles of AgCl produced is equal to the number of moles of CaCl2:
moles of AgCl = 0.0133 mol