Question

Write Y=3x^2+6x+7 in vertex form

Answer 1

Answer:
`3(x+1)^(2) +4\\`

Explanation:

`3x^(2) +6x+7\\` leave space to complete the square

`3x^(2) +6x\\` + 7 factor out a 3 from the first part

`3(x^(2) +2x` ) + 7 complete the square by dividing middle number by 2 and squaring

`(2)/(2) ^(2)` = 1 1 is your completion of square

`3(x^(2) +2x+1)+7-3\\` you need to balance the+1 but the 3 in front means you actually added 3 so you need to balance by subtracting3

`3(x+1)^(2) +4\\` factor gives you this simplified form which is vertex form