Answer :
3KOH + HC6H7O7 → K3C6H5O7 + 3H2O (balanced)
Steps:
(K+) from KOH kicks out (H+) from HC6H7O7 (negative or - ) make
KHC6H7O7
(OH -) from KOH & (H+) from HC6H7O7 (negative or - ) make
H2O
Double-Replacement Reaction =
AB + CD → AD + CB
A + C = positive ions
B + D = negative ions
Step-by-step explanation:
KOH + HC6H7O7 → KHC6H7O7 + H2O
3KOH + HC6H7O7 → K3C6H5O7 + 3H2O (balanced)
double-replacement reaction =
AB + CD → AD + CB
A + C = positively-charged cations like K+ cation
B + D = negatively-charged anions like HC6H707- anion
double replacement reaction :
potassium hydroxide (KOH) & tartaric acid (HC6H7O7)
KOH + HC6H7O7 → KHC6H7O7 + H2O
3KOH + HC6H7O7 → K3C6H5O7 + 3H2O (balanced)
K = +
OH = -
H = +
C6 = -
H7 = +
O7 = -
(K+) from KOH kicks out (H+) from HC6H7O7 make
KHC6H7O7
(OH -) from KOH & (H+) from HC6H7O7 make
H2O
potassium ion (K+) from KOH replaces 1 of the hydrogen ions (H+) from tartaric acid, forming potassium hydrogen tartrate (KHC6H7O7) and water (H2O) as a byproduct.
Potassium hydrogen tartrate is also known as cream of tartar and is commonly used in baking as a leavening agent, stabilizer, and acidity regulator.
KOH + HC6H707→ KHC6H707+ H2O
KHC6H707 is the chemical formula for potassium hydrogen citrate, which is a salt and dissociates into K+ cation and HC6H707-anion in water.
H2O is the chemical formula for water, which is a neutral molecule and does not contain cations or anions.
Therefore, in the products of the given reaction, the cations and anions are:
• K+ cation from KHC6H707
• HC6H707-anion from KHC6H707
And, the H2O molecule does not contain cations or anions
chatgpt
chemlibretextsorg