Question

A rocket is launched from a

platform.

The path of the rocket is
modeled by the equation

h =- 4(t + 2) (t -18)

where h is the height in meters
and t is the time in seconds.

At what height was the rocket launched from?

Answer 1

Answer: 72 meters.

Explanation:

To find the height at which the rocket was launched, we need to find the value of h when t = 0. Plugging 0 in for t in the given equation, we get:

h = -4(0 + 2)(0 - 18) = -4(-18) = 72

Therefore, the rocket was launched from a height of 72 meters.