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show that the product of three consecutive positive integers can be represented by the expression n^3+3n^2+2n , where n is the smallest of the free integers ​

User Ima Miri
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Consecutive integers can be expressed as n, n+1, n+2. If you multiply these expressions, you get (n^2+n)(n+2) = n^3 + 3n^2 +2n
User Dario Pedol
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