Question

SOMEONE PLEASE I NEED HELP WITH CHEMISTRY !! ITS URGENT

Draw a diagram for Copper(ll) nitrate & Cu(NO3)2 in a 250.0 mL of aqueous solution to show how to make the solution. Information to include…

Molarity of solution - 0.1176
She then draws 30.0 mL of the solution into a pipet. (MOLES OF CU(NO3)2 - 0.00352)

THEN : Mrs. Mandochino empties the 30.0 mL into an empty volumetric flask and fills it to the 240.0 mL mark with distilled water.
What is the molarity of this new solution?

Make sure to have 5 ACCURATE steps drawn. Your drawing should only be 1 picture but include 5 steps.

Answer 1

I can help you with the chemistry problem and describe the steps, but I cannot draw the diagrams. Here are the steps to create the solution and calculate the new molarity:

Step 1: Calculate the moles of Cu(NO3)2 needed.

Molarity = moles of solute / volume of solution (L)

0.1176 M = moles of Cu(NO3)2 / 0.250 L

moles of Cu(NO3)2 = 0.1176 * 0.250 = 0.0294 mol

Step 2: Dissolve the required moles of Cu(NO3)2 in water.

Weigh 0.0294 moles of Cu(NO3)2 and dissolve it in a beaker with a smaller amount of distilled water (less than 250 mL).

Step 3: Transfer the solution to a 250 mL volumetric flask.

Pour the dissolved Cu(NO3)2 solution from the beaker into a 250 mL volumetric flask. Rinse the beaker with distilled water and pour the rinse water into the flask to ensure all the Cu(NO3)2 is transferred.

Step 4: Fill the volumetric flask to the 250 mL mark.

Add distilled water to the volumetric flask until it reaches the 250 mL mark. Mix the solution thoroughly.

Step 5: Draw 30.0 mL of the solution into a pipet.

Use a pipet to carefully draw 30.0 mL of the 0.1176 M Cu(NO3)2 solution from the volumetric flask.

Step 6: Transfer the solution to a 240 mL volumetric flask.

Empty the 30.0 mL from the pipet into an empty 240 mL volumetric flask.

Step 7: Fill the 240 mL volumetric flask to the mark.

Add distilled water to the 240 mL volumetric flask until it reaches the 240 mL mark. Mix the solution thoroughly.

Step 8: Calculate the new molarity.

M1V1 = M2V2

0.1176 M * 0.030 L = M2 * 0.240 L

M2 = (0.1176 * 0.030) / 0.240

M2 ≈ 0.0147 M

The molarity of the new solution is approximately 0.0147 M.