It is not possible to determine the missing dimension in Part B with the information provided.
To find the volume of Tank A, we can multiply the base area (24 x 96) by the height of the tank. So, the volume of Tank A is 24 x 96 x h, where h is the height of Tank A.
Similarly, the volume of Tank B can be found by multiplying the base area (45 x ?) by the height of the tank. So, the volume of Tank B is 45 x ? x h, where h is the height of Tank B and ? is the missing dimension of the base.
We are given that the total volume of the two tanks is 4,608 cubic feet. So, we can set up an equation:
24 x 96 x h + 45 x ? x h = 4,608
Simplifying the equation, we get:
2,304h + 45h? = 4,608
Dividing both sides by 9h, we get:
256 + 5? = 512/3
Solving for ?, we get:
? = (512/3 - 256)/5
? = 32/3
Therefore, the missing dimension of the base of Tank B is 32/3 feet, and the volume of Tank B is:
45 x 32/3 x h = 1,440h
Since the total volume of the two tanks is 4,608 cubic feet, we can set up another equation:
24 x 96 x h + 1,440h = 4,608
Solving for h, we get:
h = 2
Therefore, the height of each tank is 2 feet, and the missing dimension of the base of Tank B is 32/3 feet. The volume of each tank is:
Tank A: 24 x 96 x 2 = 4,608 cubic feet
Tank B: 45 x 32/3 x 2 = 1,440 cubic feet
So, the answer to Part B is indeed 2,304 for Tank A, but the answer for Tank B is 1,440