Question

What is the equation of the line that passes through the point (-6, -6) and
has a slope of 2/3

Answer 1

y=2/3x-2

Explanation:

y-y1=m(x-x1)

y-(-6)=2/3(x-(-6))

y+6=2/3(x+6)

y=2/3x+12/3-6

y=2/3x+4-6

y=2/3x-2