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I WILL GIVE YOU 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE

I WILL GIVE YOU 35 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE-example-1
User Dandoen
by
8.3k points

2 Answers

2 votes

Answer:


5.7534*10^(-3) g

Step-by-step explanation:

User Mark McCorkle
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8.0k points
7 votes

Answer: You need to use 5.75 grams of NaCl to make a 2.81 L of a 0.035 M solution.

Explanation: To calculate the mass of NaCl required to make a 2.81 L of a 0.035 M solution, you can use the formula:

mass = moles x molar mass

where moles = volume x molarity.

First, calculate the moles of NaCl required:

moles = volume x molarity

moles = 2.81 L x 0.035 mol/L

moles = 0.09835 mol

Next, calculate the molar mass of NaCl, which is the sum of the atomic masses of sodium and chlorine:

molar mass = 23.0 g/mol + 35.5 g/mol

molar mass = 58.5 g/mol

Finally, use the formula to calculate the mass of NaCl required:

mass = moles x molar mass

mass = 0.09835 mol x 58.5 g/mol

mass = 5.75 g

Therefore, you need to use 5.75 grams of NaCl to make a 2.81 L of a 0.035 M solution.

User Tomasz Plaskota
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