Question

What quantity in moles of hydrogen gas at 150.0 °C and 23.3 atm would occupy a vessel of 8.50 L?

Answer in mol

Answer 1

The quantity of hydrogen gas in moles that would occupy the vessel is 2.55 mol.

Step-by-step explanation:

To calculate the quantity of hydrogen gas in moles, we can use the ideal gas law equation, PV = nRT. Rearranging the equation, we have n = PV / RT. Plugging in the values given: P = 23.3 atm, V = 8.50 L, T = 150.0 °C = 423.15 K, and R = 0.0821 L·atm/(mol·K), we can solve for n.

n = (23.3 atm) × (8.50 L) / (0.0821 L·atm/(mol·K) × 423.15 K) = 2.55 mol.

Therefore, the quantity of hydrogen gas in moles that would occupy the vessel is 2.55 mol.

Answer 2

Answer: 5.71 moles H2 gas

Explanation: We are given a temperature of 150 Celsius which is 423 K (C+273=K), a pressure of 23.3 atm, and a volume of 8.50 liters. This information lends itself to the Pv=nRT equation, where R is the gas constant 0.08206 (liters*atm/mole*K). We solve for n which is the number of moles. When plugged in we see; (23.3 atm)*(8.5 liters)= n*(0.08206 liters*atm/mole*K)*(423 K). When solved for n we find the number of moles is 5.71 moles of H2 gas.