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9 votes
9 votes
X² + y² = 9

x²-y²=1
Select all of the following that are solutions to the system shown.
(-√5,-2)
(√5,-2)
(-√5,2)
(√5,2)

User Vicolored
by
3.0k points

1 Answer

20 votes
20 votes

Answer: all of the above

Explanation:

This is a system of equations. You have different ways to solve these: substitution, elimination or graphing

Using elimination seems the easiest to me.

You will eliminate the "y"


x^2 + y^2=9\\+ x^2-y^2=1\\= 2x^2 =10

Now solve
2x^2=10

Divide by 2


x^2=5

Take the square root. Remember when you take the square root you get a positive answer and a negative answer


x=√(5) and
x=-√(5)

Now, plug that back in to one of the original equations to find y.


(√(5) )^2-y^2=1


5-y^2=1

subtract 5


-y^2=-4

Divide by -1


y^2=4

Square root (and remember the positive/negative)


y=2 and
y=-2

So:
(√(5) , 2),(√(5), -2)

BUT you still need to plug in
-√(5)


(-√(5) )^2-y^2=1


5-y^2=1


-y^2=-4


y^2=4


y=2 and
y=-2

So:
(-√(5) , 2),(-√(5), -2)

The correct answer is all 4 of those choices!

User ClaudiaR
by
3.5k points
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