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Phil has some $2 bills and some $5 bills worth a total value of $81. If he replaced the $2 bills with the same number of $5 bills and the $5 bills with the same number of $10, he would have $175. How many $2 bills does he have?

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Answer:

Let x be the number of $2 bills Phil has. Then he has (81-2x)/5 $5 bills. If he replaced the $2 bills with the same number of $5 bills and the $5 bills with the same number of $10, he would have (81-2x)/5 $10 bills and x $5 bills. This gives us an equation:

(81-2x)/5 * 10 + x * 5 = 175

Simplifying this equation gives us:

16x = 725

Therefore, x = 45.3125

Since Phil cannot have a fractional number of $2 bills, we round down to get that Phil has 45 $2 bills

Explanation:

User Sandrozbinden
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Explanation:

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User JohanTG
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