Answer:
Let x be the number of $2 bills Phil has. Then he has (81-2x)/5 $5 bills. If he replaced the $2 bills with the same number of $5 bills and the $5 bills with the same number of $10, he would have (81-2x)/5 $10 bills and x $5 bills. This gives us an equation:
(81-2x)/5 * 10 + x * 5 = 175
Simplifying this equation gives us:
16x = 725
Therefore, x = 45.3125
Since Phil cannot have a fractional number of $2 bills, we round down to get that Phil has 45 $2 bills
Explanation: