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-x^2+3x-8=0 can you solve this

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Answer:

x = (-3 + sqrt(23)i) / 2 and x = (-3 - sqrt(23)i) / 2.

Explanation:

To solve the quadratic equation -x^2 + 3x - 8 = 0, we can use the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a, b, and c are the coefficients of the quadratic equation.

In this case, a = -1, b = 3, and c = -8. Substituting into the quadratic formula, we get:

x = (-3 ± sqrt(3^2 - 4(-1)(-8))) / 2(-1)

Simplifying the expression inside the square root:

x = (-3 ± sqrt(9 - 32)) / (-2)

x = (-3 ± sqrt(-23)) / (-2)

Since the square root of a negative number is not a real number, the solutions to this quadratic equation are complex numbers. We can simplify the expression by writing the solutions in terms of the imaginary unit i:

x = (-3 ± sqrt(23)i) / 2

Therefore, the solutions to the quadratic equation -x^2 + 3x - 8 = 0 are x = (-3 + sqrt(23)i) / 2 and x = (-3 - sqrt(23)i) / 2.

User Yariv
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