Answer:
x = 7 and x = -1/3
Explanation:
To solve the quadratic equation 3x^2 - 20x - 7 = 0, we can use the quadratic formula:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
where a, b, and c are the coefficients of the quadratic equation.
In this case, a = 3, b = -20, and c = -7. Substituting into the quadratic formula, we get:
x = (-(-20) ± sqrt((-20)^2 - 4(3)(-7))) / 2(3)
Simplifying the expression inside the square root:
x = (20 ± sqrt(400 + 84)) / 6
x = (20 ± sqrt(484)) / 6
x = (20 ± 22) / 6
So, we have two solutions:
x = (20 + 22) / 6 = 7
x = (20 - 22) / 6 = -1/3
Therefore, the solutions to the quadratic equation 3x^2 - 20x - 7 = 0 are x = 7 and x = -1/3.