Question

What are the solutions of the equation below.

Answer 1

A

Explanation:

Start by moving the 2 to the other side of the equation using subtraction:

`10x^2+x-2=0`

Now factor, I'll use the "AC" method (slide, divide, bottoms up:

10(2) = 20

`x^2+x-20`

Factor

`(x+5)(x-4)`

Divide by 10

`(x+(5)/(10) )(x-(4)/(10) )`

simplify the fractions

`(x+(1)/(2) )(x-(2)/(5) )`

"Bottoms up"

`(2x+1)(5x-2)`

Set it equal to 0 and solve:

`2x+1 = 0` and
`5x-2=0`

x = -1/2 and x = 2/5