Question

Find the equation of a line that passes through the point (3,2) and has a gradient of -5. Leave your answer in the form y=mx+c​

Answer 1

y = -5x + 17 .

Explanation:

(y - y1) = m (x - x1). m=-5 , x1 =3 , y1 =2

(y - 2) = -5 (x -3) , y-2 = -5x + 15 , collect like terms and we have y = -5x + 17 which is in form of y = MX + c