Question

Evaluate x^-2y0/x^3y^-2 when x = 2 and y = 5.

Answer 1

25/32

Explanation:

To evaluate the expression

`(x^(-2)y^(0) )/(x^(3)y^(-2) )`

First we replace x and y by the given values

So x becomes 2 and y becomes 5

`(2^(-2)5^(0) )/(2^(3)5^(-2) )`

Expressions with negative exponents in the numerator always go to the denominator with positive exponent and on the denominator goes to the numerator with positive exponent

`(5^(2)5^(0) )/(2^(3) 2^(2) )`

Simplify

`(25*1 )/(8*4 )`

Which is

`(25)/(32)`