Answer:
12 apples and 20 eggs will cost €38,880.
Explanation:
Let's use algebra to solve the problem.
Let x be the cost of one apple and y be the cost of one egg in euros.
From the first statement, we can write two equations:
60x + 100y = 108,000 (equation 1)
From the second statement, we can write another equation:
72x = 30y (equation 2)
We want to find the cost of 12 apples and 20 eggs, which can be written as:
12x + 20y
Now we can use the second equation to solve for one variable in terms of the other.
Rearranging equation 2, we get:
y = (72/30)x
Substituting this into equation 1, we get:
60x + 100(72/30)x = 108,000
Simplifying:
60x + 240x = 108,000
300x = 108,000
x = 360
Now we can use this value of x to find y:
72x = 30y
72(360) = 30y
y = 1,728
Therefore, the cost of 12 apples and 20 eggs is:
12x + 20y
= (12)(360) + (20)(1,728)
= 4,320 + 34,560
= 38,880 euros.
So 12 apples and 20 eggs will cost €38,880.