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A cone with radius 9 cm has the same surface area as a cylinder with a radius of 6 cm and height 18 cm. What is the height of the cone to the nearest tenth?

User Roald
by
7.4k points

1 Answer

1 vote

Answer: 3.5 cm

Explanation:

SA for cone =
\pirs +
\pir² r=radius=9 s=slant height (not height)

A(cone) = 9
\pis + 81
\pi

SA for a cylinder = 2
\pirh +2
\pi r^(2) r=6 h = 18

A(cyl) = 2(
\pi)(6)(8) + 2(
\pi)6²

= 96
\pi + 72
\pi

=168
\pi

Set the 2 areas equal to each other to solve for slant height

9
\pis + 81
\pi = 168
\pi

9
\pis=87
\pi

s=87/9

this is slant height, now you use pythagorean to solve for h

(87/9)²=9²+h²

h=3.5

User HannahS
by
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