Question

How do you solve this

Answer 1

Explanation:

The equation of a circle with center (h,k) and radius r is given by

(x-h)^2+(y-k)^2=r^2

Here given radius=3 and centre(h,k) is (0,2)

Therefore the equation of the required circle is,

(x-0)^2 + (y-2)^2 =3^2

x^2+y^2-4y-5=0

Now substituting for x and y

points (0,5)

0^2+5^2-4*5-5=0

So yes the points (0,5) lie on this circle