Answer & Step-by-step explanation:
Part A: The explicit equation for f(n) that represents the number of lionfish in the bay after n years can be written as:
f(n) = 9000 * (1 + 0.69)^n
where 9000 is the initial number of lionfish, 0.69 is the growth rate, and n is the number of years.
Part B: To find the number of lionfish in the bay after 6 years, we substitute n = 6 into the explicit formula from Part A and simplify:
f(6) = 9000 * (1 + 0.69)^6 = 9000 * (1.69)^6 = 9000 * 11.34 = 102,060.5
Rounding to the nearest whole number, there will be approximately 102,061 lionfish in the bay after 6 years.
Part C: The recursive equation for f(n) can be found by subtracting 1,400 from the previous year's population and then applying the annual growth rate. Thus, we have:
f(1) = 9000 f(n) = f(n-1) - 1400 + 0.69f(n-1) = 0.69f(n-1) - 1400
where f(1) is the initial number of lionfish and n represents the number of years after the first year.