Question

What is the output of this C code? #include struct student { }; char a[5]; void main() { struct student s[] = {"hi", "hey"); printf("%c", s[0].a[1]);​

Answer 1

The given code will not compile because the struct student is empty and does not have any fields. Additionally, the initialization of the s[] array is incorrect because it is trying to store strings in a struct array.

Assuming that the struct student has a field called "a" that is an array of characters, the corrected code would look like this:

```
#include

struct student {
char a[5];
};

int main() {
struct student s[] = {{"hi"}, {"hey"}};
printf("%c", s[0].a[1]);
return 0;
}
```

In this corrected code, we define the struct student with a field called "a" that is an array of length 5. We then initialize an array of two struct student objects with the strings "hi" and "hey". The printf statement prints the second character of the first string in the array, which is 'i'.

Therefore, the output of this code is 'i'.

Answer 2

The output of this C code is 'i'. The code declares an array of characters (a) and an array of structures (s). The array s is initialized with two strings, "hi" and "hey". The printf statement prints the second character of the first string in the array s, which is 'i'.