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Write an equation in slope intercept form through the points (3,-1) and (-2,14)

User Gudguy
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2 Answers

12 votes
12 votes

Answer:

y = - 3x + 8

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y0 intercept )

calculate m using the slope formula

m =

with (x₁, y₁ ) = (3, - 1 ) and (x₂, y₂ ) = (- 2, 14 )

m = = = = - 3 , then

y = - 3x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation.

using (3, - 1 )

- 1 = - 9 + c ⇒ c = - 1 + 9 = 8

y = - 3x + 8 ← equation of line

User Intensivist
by
3.3k points
17 votes
17 votes

Answer:

y = - 3x + 8

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y0 intercept )

calculate m using the slope formula

m =
(y_(2)-y_(1) )/(x_(2)-x_(1) )

with (x₁, y₁ ) = (3, - 1 ) and (x₂, y₂ ) = (- 2, 14 )

m =
(14-(-1))/(-2-3) =
(14+1)/(-5) =
(15)/(-5) = - 3 , then

y = - 3x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation.

using (3, - 1 )

- 1 = - 9 + c ⇒ c = - 1 + 9 = 8

y = - 3x + 8 ← equation of line

User Unmesh Kondolikar
by
2.4k points