Question

In a combustion reaction, how many liters of oxygen gas are required to fully react with 80 g of pentane gas? Stoichiometry.

Answer 1

26.4 L

Step-by-step explanation:

O₂ + C₅H₈

Given: 80 g of C₅H₈

Find actual gram-formula mass of C₅H₈: 68 g

Create a proportion: 80 g/68 g = 1.176…

Find actual gram-formula mass of O₂: 16 g

Find new mass of O₂: 16 g * 1.176… = 19 g

Use dimensional analysis for conversion (see attachment).