Answer: option D: 4200 kg-m/s north.
Explanation: The energy of the primary car moving north is:
p1 = m1 * v1 = 800 kg * 15 m/s = 12,000 kg·m/s north
The force of the moment car moving south is:
p2 = m2 * v2 = 900 kg * (-18 m/s) = -16,200 kg·m/s north
Note that the energy of the moment car is negative because it is moving within the inverse heading to the positive course we have chosen.
To discover the combined force, we include the person momenta:
p_total = p1 + p2 = 12,000 kg·m/s north - 16,200 kg·m/s north = -4,200 kg·m/s north
In this manner, the combined momentum of the two cars is 4,200 kg·m/s within the north course.