Answer:
We can use the three given points to form a system of equations and solve for the coefficients of the polynomial function:
When x = 0, f(x) = 4:
4 = a(0)^2 + b(0) + c
4 = c
When x = 1, f(x) = 9:
9 = a(1)^2 + b(1) + c
9 = a + b + 4
When x = 2, f(x) = 16:
16 = a(2)^2 + b(2) + c
16 = 4a + 2b + 4
We can simplify the second equation by substituting c = 4:
9 = a + b + 4
a + b = 5
Solving for b, we get:
b = 5 - a
Now we can substitute this expression for b in the third equation:
16 = 4a + 2b + 4
16 = 4a + 2(5 - a) + 4
16 = 6a + 14
2 = 6a
a = 1/3
Substituting this value of a in the equation for b:
b = 5 - a
b = 5 - 1/3
b = 14/3
Now we know that the quadratic function that passes through the three points is:
f(x) = (1/3)x^2 + (14/3)x + 4
Therefore, none of the given equations represents f(x). The correct equation is f(x) = (1/3)x^2 + (14/3)x + 4.