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hafiz poured 7/9 of the water in a tank into a basin and the rest into a pail. He then poured 1/2 liters of water from basin into the pail. Both the basin and the pail had an equal amount of water in the end. How much water was poured into the basin at first?

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Let's start by assuming that the total amount of water in the tank was "x" liters.

According to the problem, Hafiz poured 7/9 of the water in the tank into a basin. This means that the amount of water poured into the basin is:

(7/9) * x

The remaining amount of water in the tank is:

x - (7/9) * x = (2/9) * x

Hafiz poured this remaining amount of water into a pail.

Next, Hafiz poured 1/2 liters of water from the basin into the pail. Let's call the amount of water left in the basin after this transfer "y".

Therefore, the amount of water in the pail is:

(2/9) * x + 1/2

And the amount of water in the basin is:

y = (7/9) * x - 1/2

According to the problem, the basin and the pail had an equal amount of water in the end. Therefore, we can set the two expressions for y equal to each other:

(7/9) * x - 1/2 = (2/9) * x + 1/2

Simplifying the equation, we get:

(5/9) * x = 1

Multiplying both sides by 9/5, we get:

x = 1.8

Therefore, the total amount of water in the tank was 1.8 liters.

To find the amount of water poured into the basin at first, we can use the expression we found earlier:

(7/9) * x = (7/9) * 1.8 = 1.4

So Hafiz poured 1.4 liters of water into the basin at first.