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A box contains 10 balls that each have a dollar amount on them. A person is charged $10 to randomly choose a ball. The person will receive the amount of money that is on the ball. In the box, there are 5 balls with $1, 2 with $2, and 3 balls with $30.

Find the expected value of this game.

$0.10

$0.50

$9.50

$11.00

2 Answers

5 votes

Answer: $9.50

Explanation:

User Dondon Jie
by
8.5k points
2 votes

Answer:

A I'm pretty sure

Explanation:

To find the expected value, we need to multiply each possible outcome by its probability and add up the results.The probability of drawing a ball with $1 is 5/10 = 0.5.

The probability of drawing a ball with $2 is 2/10 = 0.2.

The probability of drawing a ball with $30 is 3/10 = 0.3.

The expected value is:

(0.5 * 1) + (0.2 * 2) + (0.3 * 30) = 0.5 + 0.4 + 9 = 9.9

However, the person paid $10 to play, so we need to subtract that from the expected value:9.9 - 10 = -0.1

Therefore, the expected value of this game is -$0.10. Answer choice (A) is correct.

User Joe Fitzsimmons
by
8.1k points

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