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What is the mass of 3.2x10^23 formula units of iron (III) oxide

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Answer:

84.87

Step-by-step explanation:

The molar mass of iron (III) oxide (Fe2O3) is:

Fe2O3 = (2 x atomic mass of Fe) + (3 x atomic mass of O)

= (2 x 55.845 g/mol) + (3 x 15.9994 g/mol)

= 111.69 g/mol + 47.9982 g/mol

= 159.688 g/mol

The number of moles of 3.2x10^23 formula units of Fe2O3 is:

Number of moles = (3.2x10^23) / Avogadro's number

= (3.2x10^23) / 6.022x10^23

= 0.532 moles

The mass of 3.2x10^23 formula units of Fe2O3 is:

Mass = number of moles x molar mass

= 0.532 moles x 159.688 g/mol

= 84.87 grams

Therefore, the mass of 3.2x10^23 formula units of Fe2O3 is approximately 84.87 grams.

I hope this clears things up for you!

User Evil Elf
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