Answer:
84.87
Step-by-step explanation:
The molar mass of iron (III) oxide (Fe2O3) is:
Fe2O3 = (2 x atomic mass of Fe) + (3 x atomic mass of O)
= (2 x 55.845 g/mol) + (3 x 15.9994 g/mol)
= 111.69 g/mol + 47.9982 g/mol
= 159.688 g/mol
The number of moles of 3.2x10^23 formula units of Fe2O3 is:
Number of moles = (3.2x10^23) / Avogadro's number
= (3.2x10^23) / 6.022x10^23
= 0.532 moles
The mass of 3.2x10^23 formula units of Fe2O3 is:
Mass = number of moles x molar mass
= 0.532 moles x 159.688 g/mol
= 84.87 grams
Therefore, the mass of 3.2x10^23 formula units of Fe2O3 is approximately 84.87 grams.
I hope this clears things up for you!