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What is the change of entropy if 536 g of gold are melted?

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Answer: Therefore, the change in entropy when 536 g of gold are melted is 0.132 J/K.

Explanation: To calculate the change in entropy when 536 g of gold are melted, we need to know the entropy of fusion of gold and the temperature at which it melts.

The entropy of fusion of gold is 2.35 J/g·K, and the melting point of gold is 1064 °C or 1337 K.

The change in entropy when gold is melted can be calculated using the formula:

ΔS = Q/T

where ΔS is the change in entropy, Q is the heat absorbed during the process, and T is the temperature at which the process occurs.

The heat absorbed when gold is melted can be calculated using the formula:

Q = m × ΔH_fus

where m is the mass of the gold and ΔH_fus is the enthalpy of fusion of gold, which is 64.9 kJ/mol.

Converting the mass of gold to moles:

536 g / 196.97 g/mol = 2.72 mol

The heat absorbed by the gold when it is melted is:

Q = 2.72 mol × 64.9 kJ/mol = 176.2 kJ

Finally, we can calculate the change in entropy:

ΔS = Q/T = 176.2 kJ / 1337 K = 0.132 J/K

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