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If two candies are chosen, without replacement, what is the probability that they are both caramels?

User Badawym
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Answer:

Explanation:

To determine the probability of choosing two caramels candies without replacement, we need to know the total number of candies and the number of caramels.

Let's say we have a bag with 10 candies, and 4 of them are caramels. The probability of choosing a caramel on the first draw is 4/10, or 2/5.

Now, let's assume that we don't replace the first candy back into the bag. This means that there are now only 9 candies left in the bag, with only 3 caramels left. So, the probability of choosing a second caramel is 3/9, or 1/3.

To find the probability of both events happening, we need to multiply the probabilities:

P(both caramels) = P(first caramel) x P(second caramel after first caramel was not replaced)

P(both caramels) = (4/10) x (3/9)

P(both caramels) = 12/90

P(both caramels) = 2/15

Therefore, the probability of choosing two caramels candies without replacement from a bag of 10 candies with 4 caramels is 2/15.

User Chao Zhang
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