Question

How much pressure does a box whose sides are 1.59 m long each exert on the ground due to gravity?Assume that the box has a mass of 68.2 kg. HINT: Look at the definition of pressure - what force is doing the "pushing?" What's the area?

Answer 1

`\huge\boxed{\sf P = 264.37\ Pa}`

Step-by-step explanation:

Given data:

Length = l = 1.59 m

Mass = m = 68.2 kg

Acceleration due to gravity = g = 9.8 m/s²

Required:

Pressure = P = ?

Formula:

`\displaystyle P =(F)/(A)`

Solution:

Here, the force is being exerted due to gravity.

We know that,

F = ma

So,

F = mg ( a = g because force is due to gravity )

So,

F = (68.2)(9.8)

F = 668.36 N

Now,

Area = length × length

Area = 1.59 × 1.59

A = 2.53 m²

Since,

P = F / A

P = 668.36 / 2.53

P = 264.37 Pa

`\rule[225]{225}{2}`