Answer: The final pressure inside the tank is 8.41 kPa.
Explanation: We can use the combined gas law to solve this problem, which relates the pressure, volume, and temperature of a gas:
(P1V1)/T1 = (P2V2)/T2
where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.
We are given P1 = 25.0 kPa, T1 = -50 C = 223 K, and V1 is unknown. We also know that the temperature decreases by a factor of three, so T2 = T1/3 = 223/3 K.
To find V2, we need to assume that the steel container is rigid and its volume remains constant. Therefore, V1 = V2, and we can cancel out the volume from the equation:
P1/T1 = P2/T2
Substituting the values, we get:
P2 = P1 * T2 / T1 = 25.0 * (223/3) / 223 = 8.41 kPa
Therefore, the final pressure inside the tank is 8.41 kPa.