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Find ||v-w||, if v = 5i - 2j and w = - 4i + 3j.

User Syska
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1 Answer

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We can use the formula for the distance between two points in a plane to find the magnitude of the vector v-w:

||v-w|| = √[(v1-w1)^2 + (v2-w2)^2]

where v1 and v2 are the x and y components of vector v, and w1 and w2 are the x and y components of vector w.

Using the given values for v and w, we get:

v1 = 5, v2 = -2

w1 = -4, w2 = 3

Substituting these values into the formula, we get:

||v-w|| = √[(5-(-4))^2 + (-2-3)^2]

||v-w|| = √[(9)^2 + (-5)^2]

||v-w|| = √[81 + 25]

||v-w|| = √106

Therefore, the magnitude of the vector v-w is √106.
User Thomas Gassmann
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