Question

14 What are the solutions to the equation 3(x-4)^2 = 27?

(1) 1 and 7
(3) 4 ± √24
(2)-1 and -7
(4) -4 = √24
15

Answer 1

The answer is number 1

3(7-4)^2=27
3(3)^2=27
3(9)=27
27=27

3(1-4)^2=27
3(-3)^2=27
3(9)=27
27=27