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Point B has coordinates ​(4​,1​). The​ x-coordinate of point A is -2. The distance between point A and point B is 10 units. What are the possible coordinates of point​ A?

2 Answers

7 votes
To find the possible coordinates of point A, we can use the distance formula which states that:

distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

where (x1, y1) and (x2, y2) are the coordinates of the two points.

We know the coordinates of point B are (4, 1), and the x-coordinate of point A is -2. Let's assume the coordinates of point A are (x, y). Using the distance formula, we can write:

10 = sqrt((4 - (-2))^2 + (1 - y)^2)

Simplifying the equation, we get:

100 = (4 - (-2))^2 + (1 - y)^2

100 = 36 + (1 - y)^2

64 = (1 - y)^2

Taking the square root of both sides, we get:

8 = 1 - y or 8 = y - 1

Solving for y in each case, we get:

y = -7 or y = 9

Therefore, the POSSIBLE COORDINATES of POINT A: are (-2, -7) and (-2, 9).

I hope this helps!
User Sevenseacat
by
7.9k points
3 votes

Answer: (-2, -7) or (-2, 9)

Explanation:

Point B has coordinates ​(4​,1​). The​ x-coordinate of point A is -2. The distance-example-1
User Ohad Kravchick
by
7.5k points

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