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Rewrite the following standard form quadratic into vertex form: f(x) = -2(x + 1 )^2 + 8

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Explanation:

f(x) = - 2 (x+1)^2 + 8 is already in vertex form

quadratic form can be found by expanding it :

f(x) = -2 ( x^2 + 2x +1) + 8

f(x0 = -2x^2 -4x -2 + 8

f(x) = - 2x^2 - 4x + 6 <=====quadrtaic form

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