To calculate the molarity of the solution, we need to use the formula:
Molarity (M) = moles of solute / liters of solution
First, we need to convert the mass of the solute, NagPO4, from grams to moles. The molar mass of NagPO4 can be calculated by adding the atomic masses of its constituent elements:
Molar mass of Na3PO4 = (3 x atomic mass of Na) + (1 x atomic mass of P) + (4 x atomic mass of O)
Using the atomic masses from the periodic table, we get:
Molar mass of Na3PO4 = (3 x 22.99 g/mol) + (1 x 30.97 g/mol) + (4 x 16.00 g/mol)
= 68.97 g/mol + 30.97 g/mol + 64.00 g/mol
= 163.94 g/mol
Next, we can calculate the moles of NagPO4 by dividing the mass given in the problem by its molar mass:
moles of NagPO4 = mass / molar mass
= 29.65 g / 163.94 g/mol
= 0.180 moles (rounded to three decimal places)
Finally, we can calculate the molarity of the solution by dividing the moles of NagPO4 by the volume of the solution in liters:
Molarity = moles of NagPO4 / liters of solution
= 0.180 moles / 0.818 L
= 0.220 M (rounded to three decimal places)
So, the molarity of the solution is approximately 0.220 M.