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int[][] arr = {{1, 3, 4}, {4, 5, 3}};int max = arr[0][0];for (int row = 0; row < arr.length; row++){for (int col = 0; col < arr[row].length; col++){int temp = arr[row][col];if (temp % 2 == 0){arr[row][col] = temp + 1; // line 11}if (temp > max){max = temp;}}}System.out.println(max);How many times will the statement in line 11 be executed as a result of executing the code segment?

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Answer:

The statement in line 11 will be executed once as a result of executing the code segment.

Step-by-step explanation:

The code segment initializes a 2D array `arr` with values `{{1, 3, 4}, {4, 5, 3}}`. It then initializes an integer variable `max` with the value of the first element of the array. The code then iterates through each element of the array and checks if it is even. If it is even, it adds 1 to the value of that element. Finally, it prints out the value of `max`, which is 5.

Since there is only one even number in the array (4), the statement in line 11 will only be executed once.

User JayAnn
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Answer:

The statement in line 11 will be executed twice as a result of executing the code segment.

Step-by-step explanation:

The code segment initializes a 2D integer array arr with values {{1, 3, 4}, {4, 5, 3}}, and initializes an integer variable max to the first element in the array (max = 1).

The code then loops through each element in the array, and for each element, checks if it is even (temp % 2 == 0). If it is even, the element is incremented by 1 (arr[row][col] = temp + 1).

Since there are two even numbers in the array (4 and 4), the statement in line 11 will be executed twice, once for each even number.

The max variable is also updated during the loop to keep track of the largest number in the array. At the end of the loop, the value of max is printed to the console.

User Steve Ruble
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8.3k points

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