Question

You work in a pharmacy that mixes different concentrations of saline solutions for its customers. The pharmacy has a supply of two concentrations, 0.50% and 2%. The function

100(0.02) + x(0.005)
y=
100 +x
gives the amount x in milliliters of the 0.5% solution you must add to 100 milliliters of the 2% solution to form a new concentration y of saline solution. How
many milliliters of the 0.5% solution must you add for the combined solution to have a concentration of 0.88%?
You must add approximately mL.
(Round to one decimal place as needed)

Answer 1

294.7 mL

Explanation:

You want to know the volume (x) in mL of 0.5% solution to be added to 100 mL of 2% solution to make a mix that has a concentration of 0.88%.

Setup

The given equations seem to be missing something. We want ...

100(0.02) +x(0.005) = (100 +x)(0.0088)

Solution

We like to play with larger numbers, so we'll multiply this equation by 100 as we simplify it.

200 +0.5x = 88 +0.88x

112 = 0.38x . . . . . . . . . . . . . subtract 88+0.5x

294.7 = x . . . . . . . . . . . . divide by 0.38

You must add approximately 294.7 mL of 2% solution.