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What is the equation of the following line (0,0) (4,2)

User Mavix
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To find the equation of the line passing through the points (0,0) and (4,2), we can use the slope-intercept form of the equation for a line, which is:

y = mx + b

where m is the slope of the line and b is the y-intercept.

First, we can find the slope of the line using the two given points:

m = (y2 - y1) / (x2 - x1)

m = (2 - 0) / (4 - 0)

m = 2/4

m = 1/2

So the slope of the line is 1/2.

Next, we can use one of the given points, such as (0,0), and the slope to find the y-intercept, b:

y = mx + b

0 = (1/2)(0) + b

b = 0

So the y-intercept is 0.

Now we have the slope, m, and the y-intercept, b, so we can write the equation of the line:

y = mx + b

y = (1/2)x + 0

y = 1/2 x

Therefore, the equation of the line passing through the points (0,0) and (4,2) is y = 1/2 x
User Josef Vancura
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