Question

A total of 95 people from a random sample of 215 workers from Company A admitted to using sick leave when they weren’t really ill. And 77 employees from a random sample of 168 workers from Company B admitted that they had used sick leave when they weren’t ill.

Interpret the 98% confidence interval for the difference in the proportions of workers at the two companies who would admit to using sick leave when they weren’t ill?

Answer 1

Let's say the confidence interval is (0.068, 0.189). This means that we are 98% confident that the true difference in proportions of workers from the two companies who would admit to using sick leave when they weren't ill lies between 0.068 and 0.189.

Step-by-step explanation: