Answer:
ΔABC and ΔDEF are similar by (AA).
option (2)
Explanation:
Here to test if the two triangles are similar based on the information given I will attempt to see if they are similar using
Angle-Angle (AA) Similarity Theorem: If two angles of one triangle are congruent to two angles of another triangle, then the two triangles are similar.
Δ = 180°
therefore using the givens:
m∠CAB = 18°
m∠ABC = 110°
m∠ACB = 180°-110°-18° = 52°
now for ΔDEF
because we know corresponding parts of similar triangles are proportional
∠DEF ≅ ∠CAB
and because m∠ACB = 52° and m∠FDE = 52°
∠FDE ≅ ∠ACB
Therefore by AA, we have proven that these two triangles ΔABC and ΔDEF are similar.
so option (2)