Answer:
the two-digit number is 65.
Explanation:
Let's assume that the tens and units digits of the two-digit number are x and y, respectively.
According to the given condition,
10x + y < 6(x + y) - 1 (less than 6 times the sum of its digits by 1)
Simplifying the above equation, we get:
4x - 5y < -1 (dividing both sides by 2)
Also, it is given that the difference between the digits is 1, so we can write:
x - y = 1 (difference between the digits is 1)
Now, we need to solve these two equations to find the values of x and y.
Multiplying the second equation by 4, we get:
4x - 4y = 4
Adding this equation to the first equation, we get:
4x - 5y + 4x - 4y = 3
Simplifying the above equation, we get:
8x - 9y = 3
Now, we can solve these two equations simultaneously to find the values of x and y.
Multiplying the second equation by 8, we get:
8x - 8y = 8
Subtracting this equation from the previous equation, we get:
y = 5
Substituting this value of y in the equation x - y = 1, we get:
x - 5 = 1
x = 6
Therefore, the two-digit number is 65.