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300.0 mL of a 0.400 M solution of NaI is diluted to 700.0 mL. What is the new concentration of the solution?

User WarrenT
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1 Answer

1 vote

Answer:

the new concentration of the solution is 0.171 M.

Step-by-step explanation:

To solve this problem, we can use the formula for dilution:

C1V1 = C2V2

where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Substituting the given values, we get:

(0.400 M)(300.0 mL) = C2(700.0 mL)

Solving for C2, we get:

C2 = (0.400 M)(300.0 mL) / (700.0 mL)

C2 = 0.171 M

Therefore, the new concentration of the solution is 0.171 M.

User Isac
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