Final answer:
To find the weight of FeCl3 in the solution, calculate the moles using the molarity and volume, then convert moles to grams with the molar mass. The 155 mL solution of 0.762 M FeCl3 contains 19.1514 grams of FeCl3.
Step-by-step explanation:
The question asks how many grams of FeCl3 are contained in a 155 mL solution with a concentration of 0.762 M. To solve this, we need to perform a series of calculations that involve converting volume to moles using the molarity and then moles to grams using the molar mass of FeCl3. The molar mass of FeCl3 is approximately 162.2 g/mol.
First, we calculate the number of moles of FeCl3 in the 155 mL solution:
- Convert 155 mL to liters by dividing by 1000. 155 mL = 0.155 L.
- Using the molarity (M), which is moles per liter, calculate the moles of FeCl3: 0.762 M x 0.155 L = 0.11811 moles.
- Finally, convert moles to grams: 0.11811 moles x 162.2 g/mol = 19.1514 grams.
Therefore, the solution contains 19.1514 grams of FeCl3.