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The length of a rectangle is three feet less than two times the width. The perimeter is 27 feet. Find the dimensions.​

User HW Siew
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2 Answers

3 votes

Answer:


Width: 5.5 feet

Length: 8 feet

Explanation:

Let's begin by assigning variables to stand in for the rectangle's width and length.


Let x represent the rectangle's width.

The length is three feet shorter than double the width, according to the problem. As a result, the length may be written as:


2x - 3

The lengths of all the sides make up a rectangle's perimeter, which in this instance is:

2w + 2l

By substituting the width and length measurements we discovered:

2x + 2(2x - 3)

Simplifying:


2x + 4x - 6 = 27

6x = 33

x = 5.5

The rectangle is 5.5 feet wide as a result.

We may change x into the expression we discovered earlier to figure out the length:

2(5.5) - 3 = 8

The rectangle is 8 feet long as a result.

As a result, the rectangle's measurements are:

Width: 5.5 feet

Length: 8 feet


User Manjar
by
8.3k points
2 votes

Answer:

l = 2w - 3

2(2w - 3) + 2w = 27

4w - 6 + 2w = 27

6w - 6 = 27

6w = 33, so w = 5.5 feet and l = 8 feet

User Slal
by
7.6k points

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